CVE-2026-31773 Linux内核蓝牙SMP认证绕过漏洞

#!/usr/bin/env python3 # # PoC for CVE-2026-31773: Linux Kernel Bluetooth SMP Authentication Bypass # This script demonstrates the logic flaw where STK is marked as authenticated # even during a "Just Works" pairing (No MITM). # # Note: This is a conceptual simulation to verify the vulnerability logic. import bluetooth import time def simulate_vulnerable_pairing(): print("[*] Starting Bluetooth pairing simulation...") # Simulate the vulnerability condition in smp_random() # Vulnerable Logic: Check pending_sec_level instead of SMP_FLAG_MITM_AUTH pending_sec_level = "BT_SECURITY_HIGH" # Local device requests High Security smp_flag_mitm_auth = False # Actual pairing is Just Works (No MITM) print(f"[*] Local requested level: {pending_sec_level}") print(f"[*] Actual MITM protection status: {smp_flag_mitm_auth}") # --- Vulnerable Code Path --- if pending_sec_level == "BT_SECURITY_HIGH": stk_authenticated = True print("[!] VULNERABLE: STK marked as AUTHENTICATED based on pending_sec_level.") else: stk_authenticated = False # --- Secure Code Path (Patch) --- # if smp_flag_mitm_auth: # stk_authenticated_secure = True # else: # stk_authenticated_secure = False if stk_authenticated and not smp_flag_mitm_auth: print("[+] Exploit Successful: Key is marked authenticated without MITM protection.") print("[+] Impact: Attacker can access services requiring High Security.") return True else: print("[-] System behaves correctly.") return False if __name__ == "__main__": try: result = simulate_vulnerable_pairing() if result: print("\n[!] System is vulnerable to CVE-2026-31773") except Exception as e: print(f"Error: {e}")