This issue was addressed with improved checks. This issue is fixed in macOS Sequoia 15.7.2, macOS Tahoe 26.1. An app may be able to break out of its sandbox.
The following code is for security research and authorized testing only.
python
// CVE-2025-43481 macOS Sandbox Escape PoC (Conceptual)
// This is a conceptual proof of concept for demonstration purposes
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
/*
* macOS Sandbox Escape PoC for CVE-2025-43481
*
* Note: This is a conceptual demonstration code.
* Actual exploitation requires specific conditions and macOS version.
*
* Prerequisites:
* - Target: macOS Sequoia < 15.7.2 or macOS Tahoe < 26.1
* - Attacker must have a sandboxed application running with low privileges
* - Local access to the target system
*/
int main(int argc, char *argv[]) {
printf("CVE-2025-43481 macOS Sandbox Escape PoC\n");
printf("=====================================\n\n");
printf("Target: macOS Sequoia < 15.7.2, macOS Tahoe < 26.1\n");
printf("CVSS Score: 5.2 (Medium)\n");
printf("Attack Vector: Local\n\n");
printf("This vulnerability allows a sandboxed application to:\n");
printf("1. Break out of its sandbox restrictions\n");
printf("2. Access resources outside its allocated permissions\n");
printf("3. Potentially execute code with elevated privileges\n\n");
printf("Exploitation steps (conceptual):\n");
printf("1. Identify the vulnerable check mechanism in macOS\n");
printf("2. Craft specific IPC messages or system calls\n");
printf("3. Trigger the flawed validation logic\n");
printf("4. Gain unauthorized access to protected resources\n\n");
printf("Remediation:\n");
printf("- Update to macOS Sequoia 15.7.2 or later\n");
printf("- Update to macOS Tahoe 26.1 or later\n");
return 0;
}